# Practice Test

 A) 15 B) 6 C) 12 D) 13

Correct option is A

Explanation :
since $17!$ Is divisible by 9 so sum of the digits $48+x+y$ must be divisible by 9 so, $x+y$ can be $15$ or $16$ Also $17!$ Is divisble by $11$ so $|10+x-y|$ must be multiple of $11$ or zero .The only possibility is $|x-y|=1$ So, $x+y=15$

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SIMILAR QUESTIONS

Q. Which of the following is true

Q. Let P(x) be a polynomial , which when divided by x-3 and x-5 leaves remainder 10 and 6 respectively . If the polynomial is divided by (x-3)(x-5) then the remainder is

Q. The remainder obtain we 1!+2!+3!+=....11! is divided by 12 is

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